y^'-3y=4e^{5t},y(0)=5

解答

y^{^{'}} - 3 y = 4 e^{5 t}, y (0) = 5

y = 2 e^{5 t} + 3 e^{3 t}

求解步骤

y^{'} (t) - 3 y = 4 e^{5 t}

求解线性方程:

y = 2 e^{5 t} + 3 e^{3 t}

y = 2 e^{5 t} + 3 e^{3 t}

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