What is implicit (dy)/(dx),x^2+y^2=2xy ?

The answer to implicit (dy)/(dx),x^2+y^2=2xy is (dy)/(dx)=1

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implicit (dy)/(dx),x^2+y^2=2xy

implicit derivative

\frac{d y}{d x}, x^{2} + y^{2} = 2 x y

\frac{d y}{d x} = 1

Solution steps

x^{2} + y^{2} = 2 x y

Treat

y

y (x)

Differentiate both sides:

2 x + 2 y \frac{d y}{d x} = 2 (y + x \frac{d y}{d x})

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = 1

\frac{d y}{d x} = 1

\frac{d}{d t} (2 - t)

y^{^{''}} + 4 y = 0, y (0) = 0, y^{^{'}} (0) = 1

\frac{d y}{d x} = \frac{3}{2 x ^{5}}

\int \frac{1}{- x ^{2} + 2 x + 3} d x

\int \frac{7}{x ( x ^{4} + 8 )} d x

What is implicit (dy)/(dx),x^2+y^2=2xy ?
The answer to implicit (dy)/(dx),x^2+y^2=2xy is (dy)/(dx)=1