(\partial}{\partial v}(\frac{v-u)/2)

解答

\frac{\partial}{\partial v} (\frac{v - u}{2})

\frac{1}{2}

十进制

0.5

求解步骤

\frac{\partial}{\partial v} (\frac{v - u}{2})

将

u

视为常数

将常数提出:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{\partial}{\partial v} (v - u)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{2} (\frac{\partial}{\partial v} (v) - \frac{\partial}{\partial v} (u))

\frac{\partial}{\partial v} (v) = 1

\frac{\partial}{\partial v} (u) = 0

= \frac{1}{2} (1 - 0)

化简

= \frac{1}{2}

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