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tangent f(x)= 2/x ,\at x=9

解答

切线

f (x) = \frac{2}{x}, at x = 9

解答

y = - \frac{2}{81} x + \frac{4}{9}

求解步骤

找到切点:

(9, \frac{2}{9})

计算

f (x) = \frac{2}{x}

的斜率:

\frac{df ( x )}{d x} = - \frac{2}{x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{2}{81}

找到斜率 m=

- \frac{2}{81}

且穿过

(9, \frac{2}{9})

的直线:

y = - \frac{2}{81} x + \frac{4}{9}

y = - \frac{2}{81} x + \frac{4}{9}

作图

流行的例子

斜率 (3.2)(-1.2)

s l o p e (3.2) (- 1.2)

sum from n=1 to infinity of (n+1)/(n^2)

n = 1 \sum \infty \frac{n + 1}{n ^{2}}

integral of (2x^2)/(sqrt(1-4x^3))

\int \frac{2 x ^{2}}{1 - 4 x ^{3}} d x

integral from 0 to 1 of 9xe^{-x^2}

\int_{0}^{1} 9 x e^{- x^{2}} d x

slopeintercept (8,5),(6,-7)

s l o p e in t erce pt (8, 5), (6, - 7)