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tangent f(x)=4-x^2,\at x=1.154

解答

切线

f (x) = 4 - x^{2}, at x = 1.154

解答

y = - 2.308 x + 5.331716

求解步骤

找到切点:

(1.154, 2.668284)

计算

f (x) = 4 - x^{2}

的斜率:

\frac{df ( x )}{d x} = - 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 2.308

找到斜率 m=

- 2.308

且穿过

(1.154, 2.668284)

的直线:

y = - 2.308 x + 5.331716

y = - 2.308 x + 5.331716

作图

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