integral of (x^3-x)

Lösung

\int (x^{3} - x) d x

\frac{x ^{4}}{4} - \frac{x ^{2}}{2} + C

Schritte zur Lösung

\int x^{3} - x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{3} d x - \int x d x

\int x^{3} d x = \frac{x ^{4}}{4}

\int x d x = \frac{x ^{2}}{2}

= \frac{x ^{4}}{4} - \frac{x ^{2}}{2}

Füge eine Konstante zur Lösung hinzu

= \frac{x ^{4}}{4} - \frac{x ^{2}}{2} + C

n = 1 \sum \infty 3 (\frac{1}{2})^{n - 1}

\int (1 + e^{x})^{2} d x

d er i v a t i v e - 5 t (2 t^{7} - 1)^{5}

x \to 3 + lim (\frac{ln ( x )}{x - 3})

in v erse l a pl a ce \frac{s + 2}{( s ^{2} + 4 )}