y^'=sqrt(2y+39)

Lösung

y^{^{'}} = 2 y + 39

y = \frac{t ^{2}}{2} + c_{1} t + \frac{c _{1}^{2}}{2} - \frac{39}{2}

Schritte zur Lösung

y^{'} (t) = 2 y + 39

Solve separable ODE:

y = \frac{t ^{2}}{2} + c_{1} t + \frac{c _{1}^{2}}{2} - \frac{39}{2}

y = \frac{t ^{2}}{2} + c_{1} t + \frac{c _{1}^{2}}{2} - \frac{39}{2}

d er i v a t i v e f (x) = \frac{4}{x - 2}

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