integral from 2 to infinity of e^{-7p}

解答

\int_{2}^{\infty} e^{- 7 p} d p

\frac{1}{7 e ^{14}}

十进制

1.1879 E - 7

求解步骤

\int_{2}^{\infty} e^{- 7 p} d p

计算不定积分:

\int e^{- 7 p} d p = - \frac{1}{7} e^{- 7 p} + C

带入上下限计算后得:

\int_{2}^{\infty} e^{- 7 p} d p = 0 - (- \frac{1}{7 e ^{14}})

= 0 - (- \frac{1}{7 e ^{14}})

化简

= \frac{1}{7 e ^{14}}

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