y^{''}-4y^'-5y=0,y(0)=a,y^'(0)=5

Lösung

y^{^{''}} - 4 y^{^{'}} - 5 y = 0, y (0) = a, y^{^{'}} (0) = 5

y = e^{5 t} (a + \frac{5 - 5 a}{6}) - \frac{e ^{- t} ( 5 - 5 a )}{6}

Schritte zur Lösung

y^{''} (t) - 4 y^{'} (t) - 5 y = 0

Solve linear ODE:

y = e^{5 t} (a + \frac{5 - 5 a}{6}) - \frac{e ^{- t} ( 5 - 5 a )}{6}

y = e^{5 t} (a + \frac{5 - 5 a}{6}) - \frac{e ^{- t} ( 5 - 5 a )}{6}

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