What is laplacetransform 8e^{pi-t} ?

The answer to laplacetransform 8e^{pi-t} is (8e^pi)/(s+1)

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laplacetransform 8e^{pi-t}

laplace transform

8 e^{π - t}

\frac{8 e ^{π}}{s + 1}

Solution steps

L {8 e^{- t + π}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 8 e^{π} L {e^{- t}}

L {e^{- t}} : \frac{1}{s + 1}

= 8 e^{π} \frac{1}{s + 1}

Refine

8 e^{π} \frac{1}{s + 1} : \frac{8 e ^{π}}{s + 1}

= \frac{8 e ^{π}}{s + 1}

\int sin (8 x) cos (12 x) d x

\frac{d y}{d x} = - \frac{x e ^{- x^{2}}}{y}

\int \frac{1}{e ^{2 t}} d t

\int (x - 1) x^{2} - 2 x d x

t a y l or (1 + \frac{x}{2})^{- 4}

What is laplacetransform 8e^{pi-t} ?
The answer to laplacetransform 8e^{pi-t} is (8e^pi)/(s+1)