sum from n=1 to infinity of n(n-1)

Lösung

n = 1 \sum \infty n (n - 1)

divergiert

Schritte zur Lösung

n = 1 \sum \infty n (n - 1)

Seriendivergenztest anwenden:

divergiert

= divergiert

t an g e n t f (x) = 3^{x}, at x = 8

x \to 0 lim (\frac{( x + 1 )}{x})

t an g e n t f (x) = \frac{1}{x ^{5}}, (1, 1)

\int_{0}^{1} 1 + 81 x d x

x \to 3 lim (lo g_{3} (2 x^{3}))