(3+3y+3y^2)dx+(x+2xy)dy=0

Lösung

(3 + 3 y + 3 y^{2}) d x + (x + 2 x y) d y = 0

y = \frac{- x ^{3} + - 3 x ^{6} + 4 c _{1} x ^{3}}{2 x ^{3}}, y = \frac{- x ^{3} - - 3 x ^{6} + 4 c _{1} x ^{3}}{2 x ^{3}}

Schritte zur Lösung

(3 + 3 y + 3 y^{2}) d x + (x + 2 x y) d y = 0

Solve separable ODE:

y = \frac{- x ^{3} + - 3 x ^{6} + 4 c _{1} x ^{3}}{2 x ^{3}}, y = \frac{- x ^{3} - - 3 x ^{6} + 4 c _{1} x ^{3}}{2 x ^{3}}

y = \frac{- x ^{3} + - 3 x ^{6} + 4 c _{1} x ^{3}}{2 x ^{3}}, y = \frac{- x ^{3} - - 3 x ^{6} + 4 c _{1} x ^{3}}{2 x ^{3}}

d er i v a t i v e 4 4 - y

\frac{\partial}{\partial w} (4 x^{3} - x y^{2} + 3 y - 7)

\frac{\partial}{\partial x} (e^{z^{2}} + y ln (x^{2} + 5))

\frac{d y}{d x} = \frac{y}{x} + 2 x + 3

\frac{d y}{d t} = (y + 1) (y - 3), y (0) = 1