derivative of sqrt((x+1(x+2)))

Lösung

\frac{d}{d x} ((x + 1) (x + 2))

\frac{2 x + 3}{2 ( x + 1 ) ( x + 2 )}

Schritte zur Lösung

\frac{d}{d x} ((x + 1) (x + 2))

Wende die Kettenregel an:

\frac{1}{2 ( x + 1 ) ( x + 2 )} \frac{d}{d x} ((x + 1) (x + 2))

= \frac{1}{2 ( x + 1 ) ( x + 2 )} \frac{d}{d x} ((x + 1) (x + 2))

\frac{d}{d x} ((x + 1) (x + 2)) = 2 x + 3

= \frac{1}{2 ( x + 1 ) ( x + 2 )} (2 x + 3)

Vereinfache

\frac{1}{2 ( x + 1 ) ( x + 2 )} (2 x + 3) : \frac{2 x + 3}{2 ( x + 1 ) ( x + 2 )}

= \frac{2 x + 3}{2 ( x + 1 ) ( x + 2 )}

x \to 0 lim (x - 8)

\frac{d P}{d t} = - 0.02 P

\frac{d}{d x} \frac{3 ( 1 - x ^{3} ) ^{4}}{x ( 1 - x ) ^{3}}

\frac{d}{d x} (4 x^{2} - 7 x)

\int \frac{( 2 x + 1 )}{( x - 1 )} d x