derivative of ln(2x-1+2)

Lösung

\frac{d}{d x} (ln (2 x - 1) + 2)

\frac{2}{2 x - 1}

Schritte zur Lösung

\frac{d}{d x} (ln (2 x - 1) + 2)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (ln (2 x - 1)) + \frac{d}{d x} (2)

\frac{d}{d x} (ln (2 x - 1)) = \frac{2}{2 x - 1}

\frac{d}{d x} (2) = 0

= \frac{2}{2 x - 1} + 0

Vereinfache

= \frac{2}{2 x - 1}

d er i v a t i v e \frac{sin ( q ) + cos ( q )}{cos ( q )}

in v erse l a pl a ce \frac{4}{s ( s ^{2} + 2 s + 4 )}

x \to - 8 lim (3 x + 1)

\frac{d}{d x} (cos^{2} (x) + 1)

x \to 5 lim (\frac{x + 2}{x ^{2} - 5})