integral of (x+3)(x^2+6x-7)

Lösung

\int (x + 3) (x^{2} + 6 x - 7) d x

\frac{x ^{4}}{4} + 3 x^{3} + \frac{11 x ^{2}}{2} - 21 x + C

Schritte zur Lösung

\int (x + 3) (x^{2} + 6 x - 7) d x

Multipliziere aus

(x + 3) (x^{2} + 6 x - 7) : x^{3} + 9 x^{2} + 11 x - 21

= \int x^{3} + 9 x^{2} + 11 x - 21 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{3} d x + \int 9 x^{2} d x + \int 11 x d x - \int 21 d x

\int x^{3} d x = \frac{x ^{4}}{4}

\int 9 x^{2} d x = 3 x^{3}

\int 11 x d x = \frac{11 x ^{2}}{2}

\int 21 d x = 21 x

= \frac{x ^{4}}{4} + 3 x^{3} + \frac{11 x ^{2}}{2} - 21 x

Füge eine Konstante zur Lösung hinzu

= \frac{x ^{4}}{4} + 3 x^{3} + \frac{11 x ^{2}}{2} - 21 x + C

t an g e n t f (x) = (x - 1)^{2} + 1, at x = 1

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