limit as x approaches-1-of arccos(x)

解答

x \to - 1 - lim (arccos (x))

π

十进制

3.14159 \dots

求解步骤

x \to - 1 - lim (arccos (x))

代入值

x = - 1

= arccos (- 1)

使用以下普通恒等式:

arccos (- 1) = π

x - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arccos (x) π \frac{5 π}{6} \frac{3 π}{4} \frac{2 π}{3} \frac{π}{2} \frac{π}{3} \frac{π}{4} \frac{π}{6} 0 arccos (x) 18 0^{\circ} 15 0^{\circ} 13 5^{\circ} 12 0^{\circ} 9 0^{\circ} 6 0^{\circ} 4 5^{\circ} 3 0^{\circ} 0^{\circ}

= π

\frac{d}{d x} (32 x)

x \to 0 + lim (10 x ln (x))

x \to 2 - lim (\frac{- 3}{x ^{2} - 4})

l a pl a ce t r an s f or m 5 e - 3 (t - 2)

\frac{\partial}{\partial x} (3 x^{2} y + 2 x y^{2})