What is laplacetransform t-sin(t) ?

The answer to laplacetransform t-sin(t) is 1/(s^2)-1/(s^2+1)

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laplacetransform t-sin(t)

laplace transform

t - sin (t)

\frac{1}{s ^{2}} - \frac{1}{s ^{2} + 1}

Solution steps

L {t - sin (t)}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {t} - L {sin (t)}

L {t} : \frac{1}{s ^{2}}

L {sin (t)} : \frac{1}{s ^{2} + 1}

= \frac{1}{s ^{2}} - \frac{1}{s ^{2} + 1}

ln (2 x + 1)

\int_{0}^{\frac{3}{4}} 30 x d x

f (x) = x + 9 x

x \to - \infty lim (cos (x))

\frac{d}{d x} (ln (x + 1) + \frac{x}{x + 1})

What is laplacetransform t-sin(t) ?
The answer to laplacetransform t-sin(t) is 1/(s^2)-1/(s^2+1)