y^'=kx

Lösung

y^{^{'}} = k x

y = \frac{k x ^{2}}{2} + c_{1}

Schritte zur Lösung

y^{'} (x) = k x

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int k x d x

\int k x d x = \frac{k x ^{2}}{2} + c_{1}

y = \frac{k x ^{2}}{2} + c_{1}

x \to \infty lim (4 x + 7)

n \to \infty lim (\frac{n ^{100}}{5 0 ^{n}})

\frac{d}{d x} (sec (arctan (x)))

d er i v a t i v e ln (ln (\frac{x}{2 - x ^{2}}))

x \to 5 lim (x^{2} - 3 x - 10)