y^'=0.1*y-250000

Lösung

y^{^{'}} = 0.1 \cdot y - 250000

y = e^{\frac{t + c _{1}}{10}} \cdot 10 + 2500000

Schritte zur Lösung

y^{'} (t) = 0.1 \cdot y - 250000

Solve separable ODE:

y = e^{\frac{t + c _{1}}{10}} \cdot 10 + 2500000

y = e^{\frac{t + c _{1}}{10}} \cdot 10 + 2500000

\int 5 cos (π x - 3) d x

d er i v a t i v e \frac{4 x}{x ^{2} + 2}

\frac{\partial}{\partial x} (x (10 - x - y))

\int \frac{6 - 6 x}{1 - x} d x

\frac{d}{d x} (\frac{1}{8} x 64 - x^{2})