y^'=2y+x^2+7

Lösung

y^{^{'}} = 2 y + x^{2} + 7

y = - \frac{x ^{2}}{2} - \frac{x}{2} - \frac{15}{4} + c_{1} e^{2 x}

Schritte zur Lösung

y^{'} (x) = 2 y + x^{2} + 7

Solve linear ODE:

y = - \frac{x ^{2}}{2} - \frac{x}{2} - \frac{15}{4} + c_{1} e^{2 x}

y = - \frac{x ^{2}}{2} - \frac{x}{2} - \frac{15}{4} + c_{1} e^{2 x}

in v erse l a pl a ce \frac{1}{s ^{2} + 8} (- \frac{40}{33})

t an g e n t \frac{7}{2 7 x + 2}, at a = 2

\int cos (\frac{2 πn x}{L}) d x

\int \frac{1}{5 x - 1} d x

x \to \infty + lim ((1 + 2 x)^{\frac{1}{2 l n ( x )}})