y^{''}+16y^'+64y=0,y(0)=-3,y^'(0)=28

Lösung

y^{^{''}} + 16 y^{^{'}} + 64 y = 0, y (0) = - 3, y^{^{'}} (0) = 28

y = - 3 e^{- 8 t} + 4 e^{- 8 t} t

Schritte zur Lösung

y^{''} (t) + 16 y^{'} (t) + 64 y = 0

Solve linear ODE:

y = - 3 e^{- 8 t} + 4 e^{- 8 t} t

y = - 3 e^{- 8 t} + 4 e^{- 8 t} t

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