xy^'=3(x+y)

解答

x y^{^{'}} = 3 (x + y)

y = - \frac{3 x}{2} + c_{1} x^{3}

求解步骤

x y^{'} (x) = 3 (x + y)

求解线性方程:

y = - \frac{3 x}{2} + c_{1} x^{3}

y = - \frac{3 x}{2} + c_{1} x^{3}

d er i v a t i v e 1.0 3^{x}

f (x) = 2 sin (3 x)

\frac{\partial}{\partial y} (cos (x y) + x z^{2})

in v erse l a pl a ce \frac{s ^{2}}{( s ^{2} + 4 s + 4 ) ^{2}}

f (x) = \frac{4}{x ^{3}}