y^{''}-5y^'+6y=0

Lösung

y^{^{''}} - 5 y^{^{'}} + 6 y = 0

y = c_{1} e^{3 t} + c_{2} e^{2 t}

Schritte zur Lösung

y^{''} (t) - 5 y^{'} (t) + 6 y = 0

Solve linear ODE:

y = c_{1} e^{3 t} + c_{2} e^{2 t}

y = c_{1} e^{3 t} + c_{2} e^{2 t}

in v erse l a pl a ce \frac{x}{( x ^{2} + 1 ) ( x ^{2} + 9 )}

\int t (t^{2} + 1)^{8} d t

ma c l a u r in \frac{x}{1 - x ^{2}}

x \to 1 + lim (\frac{4}{( x - 1 ) ^{3}})

\int \frac{5}{1 - 9 x ^{2}} + 7 x d x