What is the solution for y^{''}+81y=0,y(0)=4,y^'(0)=7 ?

The solution for y^{''}+81y=0,y(0)=4,y^'(0)=7 is y=4cos(9t)+7/9 sin(9t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^{''}+81y=0,y(0)=4,y^'(0)=7

y^{^{''}} + 81 y = 0, y (0) = 4, y^{^{'}} (0) = 7

y = 4 cos (9 t) + \frac{7}{9} sin (9 t)

Solution steps

y^{''} (t) + 81 y = 0

Solve linear ODE:

y = 4 cos (9 t) + \frac{7}{9} sin (9 t)

y = 4 cos (9 t) + \frac{7}{9} sin (9 t)

im pl i c i t \frac{d y}{d x}, \frac{y}{x} = 0

x \to 0 lim (ln (x) sin (x))

\int_{- 2}^{7} \frac{d}{d t} ((t - 7) (1 - t)) d t

\int_{0}^{0.6} 500 x d x

d er i v a t i v e (8 x^{3} - 5 x + 2)^{π}

What is the solution for y^{''}+81y=0,y(0)=4,y^'(0)=7 ?
The solution for y^{''}+81y=0,y(0)=4,y^'(0)=7 is y=4cos(9t)+7/9 sin(9t)