What is the limit as x approaches infinity of 2x^2+5 ?

The limit as x approaches infinity of 2x^2+5 is infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

limit as x approaches infinity of 2x^2+5

x \to \infty lim (2 x^{2} + 5)

\infty

Solution steps

x \to \infty lim (2 x^{2} + 5)

Apply Infinity Property:

x \to \pm \infty lim (a x^{n} + \dots + b x + c) = \infty, a > 0,

n is even

a = 2, n = 2

= \infty

\int \frac{x ^{2} - x + 2}{x ^{3} - x ^{2} + x - 1} d x

\frac{\partial}{\partial x} (cos (z) + x y^{2})

t an g e n t f (x) = \frac{1}{4 x ^{\frac{3}{2}}}, at x = 4

\frac{d y}{d x} = 6 x^{2} y

n = 1 \sum \infty n e^{- 8 n}

What is the limit as x approaches infinity of 2x^2+5 ?
The limit as x approaches infinity of 2x^2+5 is infinity