derivative of x^2sqrt(4-x)

解

\frac{d}{d x} (x^{2} 4 - x)

\frac{- 5 x ^{2} + 16 x}{2 4 - x}

解答ステップ

\frac{d}{d x} (x^{2} 4 - x)

積の法則を適用:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = 4 - x

= \frac{d}{d x} (x^{2}) 4 - x + \frac{d}{d x} (4 - x) x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 - x) = - \frac{1}{2 4 - x}

= 2 x 4 - x + (- \frac{1}{2 4 - x}) x^{2}

簡素化

2 x 4 - x + (- \frac{1}{2 4 - x}) x^{2} : \frac{- 5 x ^{2} + 16 x}{2 4 - x}

= \frac{- 5 x ^{2} + 16 x}{2 4 - x}