maclaurin 1+x

Lösung

maclaurin

1 + x

1 + x

Schritte zur Lösung

Apply the Maclaurin Formula

= 1 + \frac{\frac{d}{d x} ( 1 + x ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( 1 + x ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( 1 + x ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 1 + \frac{1}{1 !} x + \frac{0}{2 !} x^{2} + \frac{0}{3 !} x^{3} + \frac{0}{4 !} x^{4} + \frac{0}{5 !} x^{5} + \frac{0}{6 !} x^{6} + \frac{0}{7 !} x^{7} + \frac{0}{8 !} x^{8} + \frac{0}{9 !} x^{9} + \frac{0}{10 !} x^{10}

Fasse zusammen

= 1 + x

y^{^{'}} = 4 x y^{3}

cos^{2} (x) sin (x) \frac{d y}{d x} + (cos^{3} (x)) y = 1

x \to - \infty lim (x^{2} - 2 x + 1 - x)

\int \frac{13}{( x ^{2} - 1 ) ^{2}} d x

\frac{\partial}{\partial y} (tan (x^{2} + y^{2}))