What is the tangent of f(x)= 1/(x-5),\at x=10 ?

The tangent of f(x)= 1/(x-5),\at x=10 is y=-1/25 x+3/5

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tangent of f(x)= 1/(x-5),\at x=10

tangent of

f (x) = \frac{1}{x - 5}, at x = 10

y = - \frac{1}{25} x + \frac{3}{5}

Solution steps

Find the tangent point:

(10, \frac{1}{5})

Find the slope of

f (x) = \frac{1}{x - 5} : \frac{df ( x )}{d x} = - \frac{1}{( x - 5 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{25}

Find the line with slope m=

- \frac{1}{25}

and passing through

(10, \frac{1}{5}) : y = - \frac{1}{25} x + \frac{3}{5}

y = - \frac{1}{25} x + \frac{3}{5}

g (x) = x^{2} (1 - 7 x)

\frac{d}{d x} ((\frac{x + 7}{x - 7})^{5})

\frac{d}{d x} ((ln (9))^{x})

\int (ln (y)) d y

\int \frac{( 5 x + 7 )}{( x ^{2} + 4 x + 4 )} d x

What is the tangent of f(x)= 1/(x-5),\at x=10 ?
The tangent of f(x)= 1/(x-5),\at x=10 is y=-1/25 x+3/5