9y^{''}+9y=0

解答

9 y^{^{''}} + 9 y = 0

y = c_{1} cos (t) + c_{2} sin (t)

求解步骤

9 y^{''} (t) + 9 y = 0

求解线性方程:

y = c_{1} cos (t) + c_{2} sin (t)

y = c_{1} cos (t) + c_{2} sin (t)

d er i v a t i v e 3 x^{2} e^{x} + e^{x} (x^{3} + 9)

t an g e n t f (x) = sin (π - x), at x = \frac{π}{6}

\frac{\partial}{\partial y} (x^{2} + y^{2} + 1)

\int ln (cos (w)) tan (w) d w

(2 x y) d x + (1 - x^{2}) d y = 0