What is (\partial)/(\partial y)(2x^4yz^3) ?

The answer to (\partial)/(\partial y)(2x^4yz^3) is 2x^4z^3

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(\partial)/(\partial y)(2x^4yz^3)

\frac{\partial}{\partial y} (2 x^{4} y z^{3})

2 x^{4} z^{3}

Solution steps

\frac{\partial}{\partial y} (2 x^{4} y z^{3})

Treat

x, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 x^{4} z^{3} \frac{\partial}{\partial y} (y)

Apply the common derivative:

\frac{\partial}{\partial y} (y) = 1

= 2 x^{4} z^{3} \cdot 1

Simplify

= 2 x^{4} z^{3}

d er i v a t i v e cos (2 x)

\frac{d}{d x} (\frac{x y}{x ^{2} + y ^{2} + z ^{2}})

\frac{d y}{d x} = a y - b y^{2}

l a pl a ce t r an s f or m 8 sin (4 t) - 5 cos (4 t)

\int_{- 2}^{2} 8 1^{\frac{x}{2}} d x

What is (\partial)/(\partial y)(2x^4yz^3) ?
The answer to (\partial)/(\partial y)(2x^4yz^3) is 2x^4z^3