integral from 1 to 3 of (-x^2+4x-3)

Lösung

\int_{1}^{3} (- x^{2} + 4 x - 3) d x

\frac{4}{3}

Dezimale

1.33333 \dots

Schritte zur Lösung

\int_{1}^{3} - x^{2} + 4 x - 3 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{1}^{3} x^{2} d x + \int_{1}^{3} 4 x d x - \int_{1}^{3} 3 d x

\int_{1}^{3} x^{2} d x = \frac{26}{3}

\int_{1}^{3} 4 x d x = 16

\int_{1}^{3} 3 d x = 6

= - \frac{26}{3} + 16 - 6

Vereinfache

- \frac{26}{3} + 16 - 6 : \frac{4}{3}

= \frac{4}{3}

x \to (0) lim (\frac{ln ( x )}{x})

x \to 1 + lim (\frac{∣ x - 1 ∣}{x - 1})

\frac{\partial}{\partial x} (\frac{- x}{y ^{2} + x ^{2}})

\int t^{5} ln (t) d t

d er i v a t i v e e^{(e^{(x)} - x)}