What is partialfraction (x^2)/(x^2-9) ?

The solution to partialfraction (x^2)/(x^2-9) is 1-3/(2(x+3))+3/(2(x-3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

partialfraction (x^2)/(x^2-9)

partial fractions

\frac{x ^{2}}{x ^{2} - 9}

1 - \frac{3}{2 ( x + 3 )} + \frac{3}{2 ( x - 3 )}

Solution steps

\frac{x ^{2}}{x ^{2} - 9}

Long division

\frac{x ^{2}}{x ^{2} - 9} : 1 + \frac{9}{x ^{2} - 9}

= 1 + \frac{9}{x ^{2} - 9}

Continue partial fractions on remainder:

\frac{9}{x ^{2} - 9}

Take the partial fraction of

\frac{9}{x ^{2} - 9} : - \frac{3}{2 ( x + 3 )} + \frac{3}{2 ( x - 3 )}

1 - \frac{3}{2 ( x + 3 )} + \frac{3}{2 ( x - 3 )}

\int + (x) d x

\int 4 tan^{4} (x se) c^{6} x d x

x \to - \infty lim ((1 + \frac{1}{x})^{2 x})

\int 3 x^{2} + 10 x - 5 d x

x \to - 2 - lim (- 3 x^{2} - 5 x + 3)

What is partialfraction (x^2)/(x^2-9) ?
The solution to partialfraction (x^2)/(x^2-9) is 1-3/(2(x+3))+3/(2(x-3))