What is the integral of (-8sec(x)tan(x)+5sec^2(x)) ?

The integral of (-8sec(x)tan(x)+5sec^2(x)) is -8sec(x)+5tan(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (-8sec(x)tan(x)+5sec^2(x))

\int (- 8 sec (x) tan (x) + 5 sec^{2} (x)) d x

- 8 sec (x) + 5 tan (x) + C

Solution steps

\int - 8 sec (x) tan (x) + 5 sec^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 8 sec (x) tan (x) d x + \int 5 sec^{2} (x) d x

\int 8 sec (x) tan (x) d x = 8 sec (x)

\int 5 sec^{2} (x) d x = 5 tan (x)

= - 8 sec (x) + 5 tan (x)

Add a constant to the solution

= - 8 sec (x) + 5 tan (x) + C

\frac{d}{d x} ((2 - 7 x^{\frac{3}{2}})^{2})

y^{^{'}} + e^{x} y = 1

2 x^{^{''}} + 4 x^{^{'}} + 8 x = 0, x (0) = 0, x^{^{'}} (0) = 1

\frac{d}{d θ} (e^{- i θ})

\frac{\partial}{\partial x} (ln (tan (\frac{x}{2})))

What is the integral of (-8sec(x)tan(x)+5sec^2(x)) ?
The integral of (-8sec(x)tan(x)+5sec^2(x)) is -8sec(x)+5tan(x)+C