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tangent f(x)=4x^2-4x+1,\at x=4

解答

切线

f (x) = 4 x^{2} - 4 x + 1, at x = 4

解答

y = 28 x - 63

求解步骤

找到切点:

(4, 49)

计算

f (x) = 4 x^{2} - 4 x + 1

的斜率:

\frac{df ( x )}{d x} = 8 x - 4

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 28

找到斜率 m=

28

且穿过

(4, 49)

的直线:

y = 28 x - 63

y = 28 x - 63

作图

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