What is the derivative of 1/(x+3) ?

The derivative of 1/(x+3) is -1/((x+3)^2)

What is the first derivative of 1/(x+3) ?

The first derivative of 1/(x+3) is -1/((x+3)^2)

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derivative of

\frac{1}{x + 3}

- \frac{1}{( x + 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{x + 3})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((x + 3)^{- 1})

Apply the chain rule:

- \frac{1}{( x + 3 ) ^{2}} \frac{d}{d x} (x + 3)

= - \frac{1}{( x + 3 ) ^{2}} \frac{d}{d x} (x + 3)

\frac{d}{d x} (x + 3) = 1

= - \frac{1}{( x + 3 ) ^{2}} \cdot 1

Simplify

= - \frac{1}{( x + 3 ) ^{2}}

x \to 0 lim (\frac{sin ( 7 x )}{tan ( x )})

\int \frac{2 x ^{2} + x - 8}{x ^{3} - 4 x} d x

(2 x - 1) y^{^{'}} + y^{2} = 0

y^{^{''}} + 9 y^{^{'}} + 14 y = 0, y (0) = 1, y^{^{'}} (0) = 0

x^{2} + 5

What is the derivative of 1/(x+3) ?
The derivative of 1/(x+3) is -1/((x+3)^2)
What is the first derivative of 1/(x+3) ?
The first derivative of 1/(x+3) is -1/((x+3)^2)