What is the limit as x approaches 4 of 1/(x^2-16) ?

The limit as x approaches 4 of 1/(x^2-16) is diverges

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limit as x approaches 4 of 1/(x^2-16)

x \to 4 lim (\frac{1}{x ^{2} - 16})

diverges

Solution steps

x \to 4 lim (\frac{1}{x ^{2} - 16})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 4 + lim (\frac{1}{x ^{2} - 16}) = \infty

x \to 4 - lim (\frac{1}{x ^{2} - 16}) = - \infty

= diverges

2 t^{3}

\frac{\partial}{\partial x} (\frac{1}{x ^{2}} - \frac{1}{1 - x - y})

2 x^{2} - 3

e^{- s}

y^{^{''}} - 2 y^{^{'}} - 3 y = - 5 t e^{- t}

What is the limit as x approaches 4 of 1/(x^2-16) ?
The limit as x approaches 4 of 1/(x^2-16) is diverges