What is the derivative of f(x)=x^2+6x ?

The derivative of f(x)=x^2+6x is 2x+6

What is the first derivative of f(x)=x^2+6x ?

The first derivative of f(x)=x^2+6x is 2x+6

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derivative of

f (x) = x^{2} + 6 x

2 x + 6

Solution steps

\frac{d}{d x} (x^{2} + 6 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (6 x)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (6 x) = 6

= 2 x + 6

\int \frac{1}{1 - 16 x ^{2}} d x

d er i v a t i v e e^{c o t (4 x)}

d er i v a t i v e \frac{6 x ^{2} + 8 x + 8 x}{x}

y^{^{'}} = \frac{( y ^{2} + 2 x y )}{x ^{2}}

\int e^{3 x} sin (3 x) d x

What is the derivative of f(x)=x^2+6x ?
The derivative of f(x)=x^2+6x is 2x+6
What is the first derivative of f(x)=x^2+6x ?
The first derivative of f(x)=x^2+6x is 2x+6