What is (\partial)/(\partial x)(42x^5y^6-30x^4y^5) ?

The answer to (\partial)/(\partial x)(42x^5y^6-30x^4y^5) is 210y^6x^4-120y^5x^3

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(\partial)/(\partial x)(42x^5y^6-30x^4y^5)

\frac{\partial}{\partial x} (42 x^{5} y^{6} - 30 x^{4} y^{5})

210 y^{6} x^{4} - 120 y^{5} x^{3}

Solution steps

\frac{\partial}{\partial x} (42 x^{5} y^{6} - 30 x^{4} y^{5})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (42 x^{5} y^{6}) - \frac{\partial}{\partial x} (30 x^{4} y^{5})

\frac{\partial}{\partial x} (42 x^{5} y^{6}) = 210 y^{6} x^{4}

\frac{\partial}{\partial x} (30 x^{4} y^{5}) = 120 y^{5} x^{3}

= 210 y^{6} x^{4} - 120 y^{5} x^{3}

x^{2} y^{^{''}} - 5 x y^{^{'}} - 7 y = 0

d er i v a t i v e f (x) = e^{- 6 x}

\int e^{1.2 x} d x

d er i v a t i v e 4 - x + 16

d er i v a t i v e 5 π^{6}

What is (\partial)/(\partial x)(42x^5y^6-30x^4y^5) ?
The answer to (\partial)/(\partial x)(42x^5y^6-30x^4y^5) is 210y^6x^4-120y^5x^3