What is the integral of (tan^2(x)) ?

The integral of (tan^2(x)) is -x+tan(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (tan^2(x))

\int (tan^{2} (x)) d x

- x + tan (x) + C

Solution steps

\int tan^{2} (x) d x

Rewrite using trig identities

= \int - 1 + sec^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 1 d x + \int sec^{2} (x) d x

\int 1 d x = x

\int sec^{2} (x) d x = tan (x)

= - x + tan (x)

Add a constant to the solution

= - x + tan (x) + C

\int \frac{x}{x ^{2} + 6 x + 12} d x

4 t^{2} + 1

(1 + x^{2}) + (1 + y) y^{^{'}} = 0

y = \frac{4}{3} π x^{3}

e^{\frac{z}{( z - 1 )}}