integral of ((2x^2)/7-8/3 x^4)

Lösung

\int (\frac{2 x ^{2}}{7} - \frac{8}{3} x^{4}) d x

\frac{2 x ^{3}}{21} - \frac{8 x ^{5}}{15} + C

Schritte zur Lösung

\int \frac{2 x ^{2}}{7} - \frac{8}{3} x^{4} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{2 x ^{2}}{7} d x - \int \frac{8}{3} x^{4} d x

\int \frac{2 x ^{2}}{7} d x = \frac{2 x ^{3}}{21}

\int \frac{8}{3} x^{4} d x = \frac{8 x ^{5}}{15}

= \frac{2 x ^{3}}{21} - \frac{8 x ^{5}}{15}

Füge eine Konstante zur Lösung hinzu

= \frac{2 x ^{3}}{21} - \frac{8 x ^{5}}{15} + C

\int 10 x e^{5 x} d x

in v erse l a pl a ce \frac{- s}{( s - 4 ) ^{2} ( s - 5 )}

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