integral of (2x+3)sqrt(2x+1)

Lösung

\int (2 x + 3) 2 x + 1 d x

\frac{1}{5} (2 x + 1)^{\frac{5}{2}} + \frac{2}{3} (2 x + 1)^{\frac{3}{2}} + C

Schritte zur Lösung

\int (2 x + 3) 2 x + 1 d x

Wende U-Substitution an

= \int u^{2} (u^{2} + 2) d u

Multipliziere aus

u^{2} (u^{2} + 2) : u^{4} + 2 u^{2}

= \int u^{4} + 2 u^{2} d u

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int u^{4} d u + \int 2 u^{2} d u

\int u^{4} d u = \frac{u ^{5}}{5}

\int 2 u^{2} d u = \frac{2 u ^{3}}{3}

= \frac{u ^{5}}{5} + \frac{2 u ^{3}}{3}

Setze in

u = 2 x + 1

ein

= \frac{( 2 x + 1 ) ^{5}}{5} + \frac{2 ( 2 x + 1 ) ^{3}}{3}

Vereinfache

\frac{( 2 x + 1 ) ^{5}}{5} + \frac{2 ( 2 x + 1 ) ^{3}}{3} : \frac{1}{5} (2 x + 1)^{\frac{5}{2}} + \frac{2}{3} (2 x + 1)^{\frac{3}{2}}

= \frac{1}{5} (2 x + 1)^{\frac{5}{2}} + \frac{2}{3} (2 x + 1)^{\frac{3}{2}}

Füge eine Konstante zur Lösung hinzu

= \frac{1}{5} (2 x + 1)^{\frac{5}{2}} + \frac{2}{3} (2 x + 1)^{\frac{3}{2}} + C

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