(dy)/(dx)=sec^2(x)(2+y)^2

Lösung

\frac{d y}{d x} = sec^{2} (x) (2 + y)^{2}

y = - \frac{1}{tan ( x ) + c _{1}} - \frac{2 tan ( x )}{tan ( x ) + c _{1}} - \frac{2 c _{1}}{tan ( x ) + c _{1}}

Schritte zur Lösung

\frac{d y}{d x} = sec^{2} (x) (2 + y)^{2}

Solve separable ODE:

y = - \frac{1}{tan ( x ) + c _{1}} - \frac{2 tan ( x )}{tan ( x ) + c _{1}} - \frac{2 c _{1}}{tan ( x ) + c _{1}}

y = - \frac{1}{tan ( x ) + c _{1}} - \frac{2 tan ( x )}{tan ( x ) + c _{1}} - \frac{2 c _{1}}{tan ( x ) + c _{1}}

in v erse l a pl a ce \frac{s + 6}{s ^{2} + 6 s + 25}

\int \frac{t - 3}{t + 1} d t

a re a y = x^{3} - 2 x^{2} + 2, y = 3 x^{2} + 5 x - 23

\int \frac{x ^{8}}{1 + x ^{18}} d x

d er i v a t i v e f (θ) = θ sin (θ)