What is the limit as x approaches 0+of 7sqrt(x)ln(x) ?

The limit as x approaches 0+of 7sqrt(x)ln(x) is 0

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limit as x approaches 0+of 7sqrt(x)ln(x)

x \to 0 + lim (7 x ln (x))

0

Solution steps

x \to 0 + lim (7 x ln (x))

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= 7 \cdot x \to 0 + lim (x ln (x))

Rewrite for L'Hopital

= 7 \cdot x \to 0 + lim (\frac{ln ( x )}{\frac{1}{x}})

Apply L'Hopital's Rule

: x \to 0 + lim (\frac{\frac{1}{x}}{- \frac{1}{2 x ^{\frac{3}{2}}}})

= 7 \cdot x \to 0 + lim (\frac{\frac{1}{x}}{- \frac{1}{2 x ^{\frac{3}{2}}}})

Simplify

\frac{\frac{1}{x}}{- \frac{1}{2 x ^{\frac{3}{2}}}} : - 2 x^{\frac{1}{2}}

= 7 \cdot x \to 0 + lim (- 2 x^{\frac{1}{2}})

Plug in the value

x = 0

= 7 (- 2 \cdot 0^{\frac{1}{2}})

Simplify

= 0

x \to 1 lim (e^{7 x^{5} - 7 x})

\frac{d}{d x} ((\frac{2 x}{x + 1})^{4})

\frac{d}{d x} (ln (ln (9 x)) + ln (ln (9)))

\frac{d}{d y} (e^{3 y})

\int \frac{x ^{2}}{e ^{3 x}} d x

What is the limit as x approaches 0+of 7sqrt(x)ln(x) ?
The limit as x approaches 0+of 7sqrt(x)ln(x) is 0