integral of (x^2-4x+3)

Lösung

\int (x^{2} - 4 x + 3) d x

\frac{x ^{3}}{3} - 2 x^{2} + 3 x + C

Schritte zur Lösung

\int x^{2} - 4 x + 3 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x - \int 4 x d x + \int 3 d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int 4 x d x = 2 x^{2}

\int 3 d x = 3 x

= \frac{x ^{3}}{3} - 2 x^{2} + 3 x

Füge eine Konstante zur Lösung hinzu

= \frac{x ^{3}}{3} - 2 x^{2} + 3 x + C

\int sin^{4} (2 x) cos^{3} (2 x) d x

\frac{\partial}{\partial x} ((3 x + 4 y) e^{y})

2 x y d x + (2 + x^{2}) d y = 0

l a pl a ce t r an s f or m sin (t + c)

\int \frac{x + 3}{x ^{2} 2 x + 3} d x