What is the solution for e^{kt}((dy)/(dt)+ky)=0 ?

The solution for e^{kt}((dy)/(dt)+ky)=0 is y=e^{-kt+c_{1}}

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e^{kt}((dy)/(dt)+ky)=0

e^{k t} (\frac{d y}{d t} + k y) = 0

y = e^{- k t + c_{1}}

Solution steps

e^{k t} (\frac{d y}{d t} + k y) = 0

Solve separable ODE:

y = e^{- k t + c_{1}}

y = e^{- k t + c_{1}}

2 x^{2} y y^{^{'}} + y^{2} = 2

t an g e n t (4 x - 3)^{\frac{1}{2}}

n = 2 \sum \infty \frac{3}{n \cdot ( n + 3 )}

n \to 0 lim (\frac{1}{n} sin (\frac{1}{n}))

y^{^{''}} + 25 y = 40 sin (5 x)

What is the solution for e^{kt}((dy)/(dt)+ky)=0 ?
The solution for e^{kt}((dy)/(dt)+ky)=0 is y=e^{-kt+c_{1}}