What is the derivative of x^2+x ?

The derivative of x^2+x is 2x+1

What is the first derivative of x^2+x ?

The first derivative of x^2+x is 2x+1

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derivative of

x^{2} + x

2 x + 1

Solution steps

\frac{d}{d x} (x^{2} + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d x}{d x}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d x}{d x} = 1

= 2 x + 1

\int_{- 2}^{2} (x^{3}) d x

\frac{d}{d x} (\frac{54}{x})

\int \frac{2 x - 5}{x ^{3} + 4 x ^{2} + 4 x} d x

\int \frac{1}{\frac{1}{x} + 2} d x

x \to 0 lim (5 x - 6)