What is the solution for (dy)/(dx)=tan(4x) ?

The solution for (dy)/(dx)=tan(4x) is y=-1/4 ln(cos(4x))+c_{1}

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(dy)/(dx)=tan(4x)

\frac{d y}{d x} = tan (4 x)

y = - \frac{1}{4} ln (cos (4 x)) + c_{1}

Solution steps

\frac{d y}{d x} = tan (4 x)

Substitute

\frac{d y}{d x}

with

y^{'} (x)

y^{^{'}} (x) = tan (4 x)

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int tan (4 x) d x

\int tan (4 x) d x = - \frac{1}{4} ln (cos (4 x)) + c_{1}

y = - \frac{1}{4} ln (cos (4 x)) + c_{1}

\int 16 - t^{2} d t

\frac{\partial}{\partial y} (1 - x - y)

x \to 0.1 lim (\frac{e ^{x} - 1}{x})

\int_{2}^{3} \frac{29}{3 - x} d x

f (x) = (6 x - x^{2})^{10}

What is the solution for (dy)/(dx)=tan(4x) ?
The solution for (dy)/(dx)=tan(4x) is y=-1/4 ln(cos(4x))+c_{1}