y^'=4-9x^2-6x^5

Lösung

y^{^{'}} = 4 - 9 x^{2} - 6 x^{5}

y = 4 x - 3 x^{3} - x^{6} + c_{1}

Schritte zur Lösung

y^{'} (x) = 4 - 9 x^{2} - 6 x^{5}

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int 4 - 9 x^{2} - 6 x^{5} d x

\int 4 - 9 x^{2} - 6 x^{5} d x = 4 x - 3 x^{3} - x^{6} + c_{1}

y = 4 x - 3 x^{3} - x^{6} + c_{1}

\frac{d}{d x} (cos (x) + sin (x) + \frac{1}{2} x^{2} + \frac{1}{x})

\int (3^{x} + \frac{2}{x}) d x

\int_{2}^{5} \frac{1}{x - 1} d x

\int \frac{x}{k} d x

d er i v a t i v e (4 t^{2} - t) (t^{3} - 8 t^{2} + 12)