(\partial)/(\partial x)(xe^y-yz)

解答

\frac{\partial}{\partial x} (x e^{y} - yz)

e^{y}

求解步骤

\frac{\partial}{\partial x} (x e^{y} - yz)

将

y, z

视为常数

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x e^{y}) - \frac{\partial}{\partial x} (yz)

\frac{\partial}{\partial x} (x e^{y}) = e^{y}

\frac{\partial}{\partial x} (yz) = 0

= e^{y} - 0

化简

= e^{y}

y^{^{''}} - 4 y^{^{'}} + 8 y = 0, y (0) = 9, y (\frac{π}{4}) = 7

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