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Popular >

integral from 0 to 2 of 8x-1/8 x

Solution

\int_{0}^{2} 8 x - \frac{1}{8} x d x

Solution

\frac{63}{4}

+1

Solution steps

\int_{0}^{2} 8 x - \frac{1}{8} x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 8 x d x - \int_{0}^{2} \frac{1}{8} x d x

\int_{0}^{2} 8 x d x = 16

\int_{0}^{2} \frac{1}{8} x d x = \frac{1}{4}

= 16 - \frac{1}{4}

Simplify

16 - \frac{1}{4} : \frac{63}{4}

= \frac{63}{4}

Popular Examples

sum from n=0 to infinity of 2x^{2n}

n = 0 \sum \infty 2 x^{2 n}

integral from 3 to infinity of e^{-x}

\int_{3}^{\infty} e^{- x} d x

limit as x approaches 3+of 3/(x^2-9)

x \to 3 + lim (\frac{3}{x ^{2} - 9})

integral from 0 to 0.9 of 1/(1-x)

\int_{0}^{0.9} \frac{1}{1 - x} d x

8y^{''}+2y^'-y=0

8 y^{^{''}} + 2 y^{^{'}} - y = 0

Frequently Asked Questions (FAQ)

What is the integral from 0 to 2 of 8x-1/8 x ?
The integral from 0 to 2 of 8x-1/8 x is 63/4